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A symmetric projectile spends a total of 20 seconds in the air. It reaches a peak height of 8 meters. HOw long it takes to reach its peak height? The projectile has a range of 80 meters.What is its horizontal velocity? What is the projectile's horizontal acceleration? What is the projectile's vertical acceleration?

  • Physc -

    Tr = 20/2 = 10 s. = Rise time.

    Range = Xo * T = 80 m.
    Xo * 20 = 80
    Xo = 4 m/s = Hor. component of initial
    velocity.

    a = 0 = Hor. acceleration.

    a = g = 9.81 m/s^2. = Ver. acceleration.

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