Algebra
posted by BrianP .
The length of a pool is 3 feet more than twice its width. If the perimeter of the pool is 72 feet, find the dimensions of the pool by writing and solving a system of equations.

L = 2W + 3
2L + 2W = 72
Substitute 2W+3 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation. 
The perimeter of a pool is 126 feet. The length is twice the width. Find the dimensions
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