Algebra

posted by BrianP

The length of a pool is 3 feet more than twice its width. If the perimeter of the pool is 72 feet, find the dimensions of the pool by writing and solving a system of equations.

  1. PsyDAG

    L = 2W + 3

    2L + 2W = 72

    Substitute 2W+3 for L in second equation and solve for W. Insert that value into the first equation and solve for L. Check by inserting both values into the second equation.

  2. Jose Gonzalez

    The perimeter of a pool is 126 feet. The length is twice the width. Find the dimensions

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