Greg teaches martial arts. He charges a one time processing fee of $5.00 and the cost of classes are shown below. let x represent the number of classes and y represent the cost of the classes. Based on the information, what will it cost to take 10 classes?
(x) classes 1 2 3 4
(y)cost of $15 $27 $39 $51
classes:
so I was able to figure out the cost goes up by $12 for each class.
that will give me $123 for 10 classes and then I have to add the $5 processing fee- giving me $128 as my answer.
Is this correct? Is there a different way of solving this using x and y?
Thanks for your help
If it's $12/class then 10 classes would cost 10*12 = $120 and that + a $5.00 processing fee would make $125 wouldn't it?
It isn't $12 a class but from the numbers they give, for example one class =$15, two classes =$27, three classes=$39, and four classes=$51
so the difference between each class is $12; not each class costs $12.
so to figure out 5 classes I added $12 to $51 dollars, getting$63; then I added $12 to that to get$75 dollars for 6 classes and so on until I got to 10 classes and it =$123 plus $5 fee.
Do you see how I did my work
OK. So it's 15 + 12*9 + 5 = 15 + 108 + 5 which is 128 as you had.
ok, Thank you
Yes, your approach is correct. The cost of the classes increases by $12 for each additional class. Therefore, to find the cost of taking 10 classes, you can start with the cost of the first class, which is $15, and then add $12 for each additional class (10 - 1 = 9 additional classes):
Cost of 10 classes = Cost of 1 class + (Number of additional classes) * (Cost increase per class)
= $15 + 9 * $12
= $15 + $108
= $123
So the cost of taking 10 classes is $123.
To verify this answer using the x and y representation, you can plot the data points (x, y) given in the table and observe the linear relationship between the number of classes and the cost. From the table, you can see that for each additional class, the cost increases by $12. So you have a linear equation in the form y = mx + b, where m represents the cost increase per class and b represents the initial cost:
y = 12x + 3
To find the cost of 10 classes, you substitute x = 10 into the equation:
y = 12 * 10 + 3
= 120 + 3
= 123
So, using the x and y representation, the cost of taking 10 classes is also $123.
Remember to add the one-time processing fee of $5 to get the total cost:
Total cost = Cost of 10 classes + Processing fee
= $123 + $5
= $128
Therefore, your final answer is correct. It will cost $128 to take 10 classes, including the one-time processing fee.