Calculus Please help!
posted by ALI .
The differential of the function y=(x^2+6)^3 is
dy=______dx.
When x=2 and dx=0.05, the differential dy=_______?
A) dy=______dx?
B) the differential dy=_______?

dy/dx = 3(x^2 + 6)^2
dy = 3(x^2 + 6)^2 dx
when x = 2 and dx = .05
dy = ......
just plug in the above values.
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