math(algebra)
posted by Ayriana .
Find the distance between A and B.
A= the coordinates ( 6, 1)
B= the coordinates ( 2, 3)
answer choices are:
A. 8 units
B. 16 units
C. 2 times the square root of 2 units
D. 4 times the square root of 2 units

the distance is the length of the hypotenuse of the right triangle whose legs are 4 and 4
Looks like (D) 
3  1 = 4
2  6 = 4
sqrt [(4)^2 + (4)^2] = sqrt (2*16)
= 4 sqrt 2 
HOW DO YOU GET THAT AS A ANSWER PLEASE? :)

thank u guys so much!! <3
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