A force of 10.0 newtons acts at an angle 20.0 degrees from vertical. What are the horizontal and vertical components of the force?
horizontal 10 sin 20
vertical 10 cos 20
you did not specify up or down or right or left so you do the signs
a force of 6.00 newtons on a car's bumper makes an angle of 28.5 degrees with the ground. what is the vertical component of this force vector
To find the horizontal and vertical components of a force, you can use trigonometry. Let's call the horizontal component "Fx" and the vertical component "Fy".
To find Fx, we need to find the side adjacent to the angle. We can use cosine, which is adjacent/hypotenuse:
cos(angle) = Fx / force
Rearranging the equation, we can solve for Fx:
Fx = force * cos(angle)
Substituting the given values, we get:
Fx = 10.0 N * cos(20.0°) ≈ 9.40 N
So, the horizontal component of the force is approximately 9.40 newtons.
To find Fy, we need to find the side opposite the angle. We can use sine, which is opposite/hypotenuse:
sin(angle) = Fy / force
Rearranging the equation, we can solve for Fy:
Fy = force * sin(angle)
Substituting the given values, we get:
Fy = 10.0 N * sin(20.0°) ≈ 3.42 N
So, the vertical component of the force is approximately 3.42 newtons.
To find the horizontal and vertical components of a force, you need to use trigonometry. In this case, we have a force of 10.0 newtons acting at an angle of 20.0 degrees from the vertical.
First, let's assign the given values:
Force = 10.0 N
Angle = 20.0 degrees
To find the vertical component, we use the sine function. The vertical component is given by:
Vertical component = Force * sin(angle)
Vertical component = 10.0 N * sin(20.0 degrees)
Now we can substitute the values into the equation and calculate the vertical component:
Vertical component = 10.0 N * sin(20.0 degrees)
Vertical component ≈ 3.42 N (rounded to two decimal places)
To find the horizontal component, we use the cosine function. The horizontal component is given by:
Horizontal component = Force * cos(angle)
Horizontal component = 10.0 N * cos(20.0 degrees)
Now we can substitute the values into the equation and calculate the horizontal component:
Horizontal component = 10.0 N * cos(20.0 degrees)
Horizontal component ≈ 9.40 N (rounded to two decimal places)
Therefore, the horizontal component of the force is approximately 9.40 Newtons, and the vertical component is approximately 3.42 Newtons.