A line in coordinate plane contains the points P(2, -7) and Q(-4, -1). What point is the midpoint of PQ?
P(2,-7), M(x,y), Q(-4.-1)
X = (x1+x2)/2 = (2+(-4))/2 = -1.
Y = (y1+y2)/2 = (-7+(-1))/2 = -4.
M(-1,-4)
To find the midpoint of a line segment, you can use the midpoint formula:
Midpoint (M) = ((x1 + x2)/2, (y1 + y2)/2)
In this case, point P has coordinates P(2, -7) and point Q has coordinates Q(-4, -1).
1. Substitute the x-coordinates of points P and Q into the formula: ((x1 + x2)/2) = ((2 + (-4))/2) = (-2/2) = -1.
2. Substitute the y-coordinates of points P and Q into the formula: ((y1 + y2)/2) = ((-7 + (-1))/2) = ((-8)/2) = -4.
Therefore, the midpoint of PQ is M(-1, -4).