A 1.60 meter tall woman is standing at the bottom of a freshwater pool. If the bottom pool is 8.00 meters deep, what is the pressure difference between the woman's feet and the top of her head?
rho g h = 1000 kg/m^3 * 9.81 m/s^2 * 1.6 m in Pascals
depth does not matter, looking for difference
So does this mean that when you multpily it all, 15,969 is the pressure difference between her head and her feet?
That sounds about right.
One atmosphere is about 101,325 Pascals
that is about 10 meters of water
so about 10,000 Pascals/meter
To find the pressure difference between the woman's feet and the top of her head, we need to consider the difference in pressure due to the depth of the pool.
The pressure at a certain depth in a fluid (such as water) is given by the equation: P = ρ * g * h, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.
To calculate the pressure difference between the woman's feet and the top of her head, we need to calculate the pressure at each location and then find the difference.
1. Calculate the pressure at the woman's feet:
Depth at the woman's feet = 0 meters (since she is standing at the bottom of the pool)
Pressure at the woman's feet = ρ * g * h
2. Calculate the pressure at the top of her head:
Depth at the top of her head = 8 meters (depth of the pool)
Pressure at the top of her head = ρ * g * h
3. Find the pressure difference:
Pressure difference = Pressure at the top of her head - Pressure at her feet
To calculate the pressure difference, we need the density of the fluid (water) and the acceleration due to gravity. The density of fresh water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Given this information, we can perform the calculations and find the pressure difference between the woman's feet and the top of her head.