A sample of oxygen gas at 295 kPa takes up 456 L of space at standard temperature (the “T” in STP). What is the new volume when the pressure is lowered to standard pressure (the “P” in STP)?
p1v1 = p2v2
To find the new volume when the pressure is lowered to standard pressure (STP), we can use Boyle's Law, which states that for a given amount of gas at a constant temperature, the pressure and volume are inversely proportional.
Let's break down the given information:
Pressure (P1) = 295 kPa
Volume (V1) = 456 L
Standard pressure (P2) at STP is 101.3 kPa.
Using Boyle's Law, we can set up the equation:
P1 * V1 = P2 * V2
Substituting the given values:
295 kPa * 456 L = 101.3 kPa * V2
Now, we can solve for V2 by rearranging the equation:
V2 = (P1 * V1) / P2
Plugging in the values:
V2 = (295 kPa * 456 L) / 101.3 kPa
V2 ≈ 1330 L
Therefore, the new volume when the pressure is lowered to standard pressure is approximately 1330 L.