5.00 mL of 2.00x10^-3M Fe(NO3)3 is mixed with 4.03 mL of 2.00x10^-3M NaSCN and 1.08 mL of 0.1M HNO3, for a total volume of 10.11 mL.
a) What is the initial concentration of the Fe(NO3)3 in the mixed solution?
b) What is the initial concentration of the NaSCN in the mixed solution?
Well, well, well. It seems like we have a mathematical challenge at hand. Don't worry, I'm here to clownishly help you out!
a) To find the initial concentration of Fe(NO3)3, we can use the equation:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Let's plug in the numbers we have:
C1 * 5.00 mL = 2.00x10^-3M * 10.11 mL
Now, let's solve for C1:
C1 = (2.00x10^-3M * 10.11 mL) / 5.00 mL
Calculating that, we get:
C1 = 4.044x10^-3M
Therefore, the initial concentration of Fe(NO3)3 in the mixed solution is 4.044x10^-3M.
b) We can follow the same logic to find the initial concentration of NaSCN:
C1 * 4.03 mL = 2.00x10^-3M * 10.11 mL
Solving for C1 gives us:
C1 = (2.00x10^-3M * 10.11 mL) / 4.03 mL
Working it out, we get:
C1 = 5.024x10^-3M
So, the initial concentration of NaSCN in the mixed solution is 5.024x10^-3M.
And there you have it! The initial concentrations of Fe(NO3)3 and NaSCN in the mixed solution. Hope that brought a little mathematical chuckle to your day!
To find the initial concentrations of Fe(NO3)3 and NaSCN in the mixed solution, we need to consider the volumes and concentrations of the individual solutions that were mixed together.
Given:
Volume of Fe(NO3)3 solution (V1) = 5.00 mL
Concentration of Fe(NO3)3 solution (C1) = 2.00x10^-3 M
Volume of NaSCN solution (V2) = 4.03 mL
Concentration of NaSCN solution (C2) = 2.00x10^-3 M
Total volume of mixed solution (Vt) = 10.11 mL
a) To find the initial concentration of Fe(NO3)3 in the mixed solution:
We can use the principle of dilution, which states that the final concentration of a solution can be calculated by multiplying the initial concentration by the volume ratio.
The volume ratio is defined as the ratio of the final volume (Vt) to the initial volume (V1).
Volume ratio (R1) = Vt / V1 = 10.11 mL / 5.00 mL = 2
Therefore, the initial concentration of Fe(NO3)3 in the mixed solution (C1') can be calculated as:
C1' = C1 * R1 = 2.00x10^-3 M * 2 = 4.00x10^-3 M
So, the initial concentration of Fe(NO3)3 in the mixed solution is 4.00x10^-3 M.
b) The same principle can be applied to find the initial concentration of NaSCN in the mixed solution:
Volume ratio (R2) = Vt / V2 = 10.11 mL / 4.03 mL ≈ 2.51
The initial concentration of NaSCN in the mixed solution (C2') can be calculated as:
C2' = C2 * R2 = 2.00x10^-3 M * 2.51 = 5.02x10^-3 M
Therefore, the initial concentration of NaSCN in the mixed solution is 5.02x10^-3 M.