Another variety of R&Ns has a different set of magical (yet mathematical) properties. Remove exactly 4 candies and 1 additional candy appears in the bag. According to the package, a bag contains 50 candies. What is the maximum number of canies that this variety of R&Ns will yield?
To determine the maximum number of candies that this variety of R&Ns can yield, we need to find the minimum number of times we can remove 4 candies and have 1 additional candy appear in the bag until no more candies can be removed.
Let's start with the given number of candies in the bag, which is 50. We will remove 4 candies and add 1 additional candy, resulting in a total decrease of 3 candies. So, after one iteration, we will have 50 - 3 = 47 candies.
We need to repeat this process until we can no longer remove 4 candies from the remaining amount. Let's continue:
47 - 3 = 44
44 - 3 = 41
41 - 3 = 38
38 - 3 = 35
35 - 3 = 32
32 - 3 = 29
29 - 3 = 26
26 - 3 = 23
23 - 3 = 20
20 - 3 = 17
17 - 3 = 14
14 - 3 = 11
11 - 3 = 8
8 - 3 = 5
Now, as we can see, removing 4 candies from the remaining 5 candies is not possible. Therefore, the maximum number of candies that this variety of R&Ns will yield is 5.