Copper Oxide + Carbon -> Copper + Carbon Dioxide
Calculate the mass of carbon needed to obtain 63.5g of copper from 79.5g of Copper Oxide
2CuO + C==> CO2 + 2Cu
Forget the 79.5g CuO. If you want 63.5 g Cu, that is 63.5/63.5 = 1 mol Cu. So you need 1/2 mol C and that is 6 g.
To solve this problem, we need to balance the equation first:
Copper Oxide + Carbon -> Copper + Carbon Dioxide
Now, let's calculate the molar masses of the substances involved:
Copper Oxide (CuO): Cu - 63.55 g/mol, O - 16.00 g/mol
Carbon (C): C - 12.01 g/mol
Copper (Cu): Cu - 63.55 g/mol
Carbon Dioxide (CO2): C - 12.01 g/mol, O - 16.00 g/mol
Next, we need to determine the number of moles for copper oxide and copper:
Number of moles = Mass / Molar Mass
For Copper Oxide:
Number of moles of CuO = 79.5 g / (63.55 g/mol + 16.00 g/mol) = 0.79 mol
For Copper:
Number of moles of Cu = 63.5 g / 63.55 g/mol = 1.00 mol
Since the balanced equation tells us that the stoichiometric ratio between Copper Oxide and Carbon is 1:1, we can say that 1 mole of Copper Oxide reacts with 1 mole of Carbon to produce 1 mole of Copper.
Therefore, the number of moles of Carbon needed can be calculated as:
Number of moles of C = Number of moles of CuO = 0.79 mol
Now, let's calculate the mass of Carbon needed:
Mass of C = Number of moles of C x Molar Mass of C
Mass of C = 0.79 mol x 12.01 g/mol = 9.49 g
Therefore, approximately 9.49 grams of carbon are needed to obtain 63.5 grams of copper from 79.5 grams of Copper Oxide.