in which of the following pairs of compounds are both members of the pair molecular compounds?

PCl3 and LiBr

CCl4 and KOH

NaH and CaF2

more than one correct response

no correct response

if more than one response please show all the correct answers

thanks

You need to know the difference between ionic and covalent compounds.

To determine whether a compound is molecular or not, we need to understand the difference between molecular compounds and ionic compounds.

Molecular compounds are formed when two or more nonmetals bond together by sharing electrons. These compounds have covalent bonds and usually have low melting and boiling points. On the other hand, ionic compounds are formed when a metal and a nonmetal bond together through the transfer of electrons. These compounds have high melting and boiling points.

Now, let's analyze the pairs given:

1. PCl3 and LiBr:
- PCl3 consists of phosphorus (nonmetal) and chlorine (nonmetal). It is a molecular compound since it contains covalent bonds.
- LiBr consists of lithium (metal) and bromine (nonmetal). It is an ionic compound since it contains ionic bonds.
Therefore, PCl3 is a molecular compound, but LiBr is an ionic compound. This pair does not have both compounds as molecular compounds.

2. CCl4 and KOH:
- CCl4 consists of carbon (nonmetal) and chlorine (nonmetal). It is a molecular compound due to covalent bonding.
- KOH consists of potassium (metal) and hydroxide (nonmetal). It is an ionic compound due to ionic bonding.
Thus, CCl4 is a molecular compound, but KOH is an ionic compound. This pair does not have both compounds as molecular compounds.

3. NaH and CaF2:
- NaH consists of sodium (metal) and hydrogen (nonmetal). It is an ionic compound because it contains ionic bonding.
- CaF2 consists of calcium (metal) and fluorine (nonmetal). It is an ionic compound due to ionic bonding.
Both NaH and CaF2 are ionic compounds. This pair does not have both compounds as molecular compounds.

In conclusion, there is no correct response because none of the pairs have both members classified as molecular compounds.

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