If 7000 dollars is invested in a bank account at an interest rate of 7 per cent per year.

A) Find the amount in the bank after 6 years if interest is compounded annually?

B) Find the amount in the bank after 6 years if interest is compounded quaterly?

C) Find the amount in the bank after 6 years if interest is compounded monthly?

D) Finally, find the amount in the bank after 6 years if interest is compounded continuously?

A=?
B=?
C=?
D=?

Thanks again guys!

$4000 is invested at 9% compounded quarterly. In how many years will the account have grown to $14,500? Round your answer to the nearest tenth of a year

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To find the amount in the bank after a certain period of time with different compounding frequencies, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A = the final amount
P = the principal amount (initial investment) = $7000
r = annual interest rate (in decimal form) = 0.07
n = the number of times that interest is compounded per year
t = the number of years

Now, let's calculate the amounts for each case:

A) Compounded Annually (n = 1)
Using the formula:
A = 7000(1 + 0.07/1)^(1*6)
A = 7000(1.07)^6
A ≈ $10,931.47

So, the amount in the bank after 6 years with annual compounding is approximately $10,931.47.

B) Compounded Quarterly (n = 4)
Using the formula:
A = 7000(1 + 0.07/4)^(4*6)
A = 7000(1.0175)^24
A ≈ $11,005.07

Therefore, the amount in the bank after 6 years with quarterly compounding is approximately $11,005.07.

C) Compounded Monthly (n = 12)
Using the formula:
A = 7000(1 + 0.07/12)^(12*6)
A ≈ $11,039.88

The amount in the bank after 6 years with monthly compounding is approximately $11,039.88.

D) Compounded Continuously
Using the formula:
A = P*e^(rt)
A = 7000*e^(0.07*6)
A ≈ $11,051.27

The amount in the bank after 6 years with continuous compounding is approximately $11,051.27.

So, the answers are:

A) $10,931.47
B) $11,005.07
C) $11,039.88
D) $11,051.27

B)

compounded quarterly
----> i = .07/4 or .0175, and n = 6(4) or 24
amount = 7000(1.0175)^24
= $ 10,615.10

Do A and C the same way

D
amount = 7000 e^(6(.07))
= $ 10,653.73