WRITE DOWN REACTION OF HYDROLYSIS OF NH4NO2 IN NET IONIC FORM. INDICATE REACTION OF MEDIUM.

What is reaction of medium?

NH4^+ + 2H2O + NO2^-==> NH3 + H3O^+ + HNO2 + OH^- and you can combine the H3O^+ and OH^- on the right to form 2H2O, then cancel the 2H2O on the left to leave you with
NH4^+ + NO2^- ==> NH3 + HNO2

The hydrolysis of NH4NO2 involves the breaking down of NH4NO2 into its constituent ions in the presence of water. The net ionic equation for the hydrolysis of NH4NO2 in an acidic medium can be written as follows:

NH4NO2 + H2O → NH4+ + NO2- + H3O+

In this reaction, NH4NO2 reacts with water to yield NH4+ (ammonium ion), NO2- (nitrite ion), and H3O+ (hydronium ion).

It is important to note that the hydrolysis of NH4NO2 occurs in an acidic medium due to the presence of H3O+ ions.

To determine the net ionic equation for the hydrolysis of NH4NO2, we first need to identify the ions present in the reaction. NH4NO2 is made up of the ammonium ion (NH4+) and the nitrite ion (NO2-).

Now let's consider the hydrolysis reaction in an aqueous medium, where water (H2O) is present. Water can act as both an acid and a base during hydrolysis reactions.

The hydrolysis reaction of NH4NO2 involves the transfer of a proton (H+) between water and the ammonium ion. The balanced molecular equation is:

NH4NO2 + H2O → NH3 + H3O+ + NO2-

In this reaction, water acts as an acid and donates a proton (H+) to the ammonium ion, forming ammonia (NH3) and hydronium ion (H3O+). The nitrite ion (NO2-) remains unchanged.

To obtain the net ionic equation, we need to remove the spectator ions – the ions that appear on both sides of the equation unchanged. In this case, the nitrite ion (NO2-) is a spectator ion.

The net ionic equation for the hydrolysis of NH4NO2 in an aqueous medium is:

NH4+ + H2O → NH3 + H3O+

This equation shows only the species that are directly involved in the reaction.

Note: The medium in this hydrolysis reaction is water (H2O).