# Chemistry

posted by Meredith

A+2B--->2C Kc=2.27
2c--->D Kc=0.144

Calculate the equilibrium constant for the reaction
D--->A+2B

1. DrBob222

Add eqn 1 to eqn 2 to obtain
A+2B ==> 2C
2C ==> D
------------
A + 2B ==> D so K' = k1*k2.
You want the reverse of this rxn; therefore, you want 1/K'.

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