if I dilute 250 of mL of 2.4 M lithium hydroxide solution so that it's new volume is 750 mL, what is the concentration of the solution?
1/3 of the original concentration
2.4 x (250/750) = ?
To find the new concentration of the solution after dilution, we can use the equation:
C1 x V1 = C2 x V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration of the solution
V2 = final volume of the solution
Given that:
C1 = 2.4 M
V1 = 250 mL
V2 = 750 mL
Let's substitute these values into the equation:
2.4 M x 250 mL = C2 x 750 mL
Now, we can solve for C2 (the final concentration):
(2.4 M x 250 mL) / 750 mL = C2
600 M mL / 750 mL = C2
C2 = 0.8 M
Therefore, the concentration of the solution after dilution is 0.8 M.