a+1 a-1 B+1
_________ = _______ + _________
B B a
Solve for A.
Note: I set up problems with underlines so they can look like fractions. That's what they are.
If you mean
(a+1)/b = (a-1)/b + (b+1)/a
((a+1)-(a-1))/b = (b+1)/a
2/b = (b+1)/a
2a = (b+1)/b
a = (b+1)/(2b)
To solve for A in the given equation:
a + 1 a - 1 B + 1
______ = _______ + _______
B B a
First, let's eliminate the fractions by finding a common denominator for all three terms, which is B.
To do this, multiply all terms of the equation by B:
B(a + 1) = B(a - 1) + B(B + 1)
Now expand the equation:
aB + B = aB - B + B^2 + B
Next, combine like terms:
aB + B = aB + B^2
Now, subtract aB from both sides of the equation:
B = B^2
This equation states that B is equal to its own square, which only holds true if B = 0 or B = 1.
If B = 0, the equation becomes:
0 = 0
This is true for any value of a.
If B = 1, the equation becomes:
1 = 1
Again, this is true for any value of a.
Therefore, the value of A cannot be determined from the given equation.