The compound sodium sulfate is soluble in water. When this compound dissolves in water, which ion listed below would be present in solution?
You didn't list any but the ions present will be Na^+ and SO4^2-
The compound sodium sulfate is soluble in water. When this compound dissolves in water, which ion listed below would be present in solution?
A. SO4^2-
B. S^2-
C. O^2-
D. Na2^2+
When sodium sulfate (Na2SO4) dissolves in water, it dissociates into its constituent ions. The ions present in solution would be:
1. Sodium ions (Na+): Each sodium sulfate molecule dissociates into two sodium ions, Na+.
2. Sulfate ions (SO42-): Each sodium sulfate molecule dissociates into one sulfate ion, SO42-.
Therefore, when sodium sulfate dissolves in water, the ions present in the solution would be sodium ions (Na+) and sulfate ions (SO42-).
To determine the ions present in a solution of sodium sulfate (Na2SO4), we need to understand the ionic nature of the compound and the dissociation process.
Sodium sulfate is an ionic compound consisting of sodium ions (Na+) and sulfate ions (SO4^2-). In water, ionic compounds dissociate or break apart into their constituent ions.
When sodium sulfate dissolves in water, the ionic bonds between sodium and sulfate are weakened, and the compound dissociates into its respective ions:
Na2SO4(s) → 2Na+(aq) + SO4^2-(aq)
So, the ions present in the solution would be sodium ions (Na+) and sulfate ions (SO4^2-).