Suppose you have information that the
average stress score of students in
online activities is 13.15. Using Minitab,
compute a one sample t-test to find out whether the stress scores reported by your
sample are significantly different from those of the population of online students.
The numbers are 15,19,16,17,18,19,18,17,
15,16
To conduct a one-sample t-test using Minitab, follow the steps below:
Step 1: Open Minitab and input the data.
Enter the stress scores given in your question into a column in Minitab. Let's assume you name this column "Stress_Scores". The data should look like this:
Stress_Scores
15
19
16
17
18
19
18
17
15
16
Step 2: Perform the t-test.
Go to "Stat" > "Basic Statistics" > "1-Sample t". In the dialog box that appears, select the column "Stress_Scores" as the "Variable". Under "Test mean", enter the known average stress score of 13.15. Finally, click "OK" to perform the t-test.
Step 3: Interpret the results.
After performing the test, Minitab will display the output. Look for the p-value, which is the probability of obtaining a result as extreme as the observed data if the null hypothesis is true.
If the p-value is less than your chosen significance level (e.g., 0.05), you can reject the null hypothesis and conclude that there is a significant difference between the stress scores reported by your sample and the population of online students. On the other hand, if the p-value is greater than your significance level, you fail to reject the null hypothesis and conclude that there is not enough evidence to demonstrate a significant difference.
It's important to note that the steps mentioned here assume that you have a basic working knowledge of Minitab. If you'd like a more detailed explanation of each step or have any specific questions about the process, please let me know.