car traveling at 22 m/s hits a stone wall . The driver, who is wearing a shoulder harness and seat belt, moves forward 1.05 m as the car stops. Assuming his acceleration is uniform, find his average velocity during the collision
22/2 = 11 m/s
trick:
during constant linear acceleration the average speed = (final speed + starting speed)/2
Damon can u look at my question plz
I do not know what your questions is, do not see name on list
car initially moving at 19 m/s brakes with an acceleration of 2.97 m/s2. How long will it take for the car to stop in seconds?
To find the average velocity during the collision, we need to use the equation:
average velocity = displacement / time
We are given the displacement (1.05 m), but we need to determine the time it took for the car to stop.
To find the time, we can use the equation of motion:
final velocity = initial velocity + (acceleration * time)
In this case, the initial velocity is 22 m/s and the final velocity is 0 m/s since the car stops.
0 m/s = 22 m/s + (acceleration * time)
Rearranging the equation, we get:
acceleration * time = -22 m/s
Now, since we are assuming the acceleration is uniform, we can use the average acceleration to find the time. The average acceleration can be calculated by dividing the change in velocity by the time taken:
average acceleration = (final velocity - initial velocity) / time
Since the final velocity is 0 m/s and the initial velocity is 22 m/s, the average acceleration is:
average acceleration = (0 m/s - 22 m/s) / time
Simplifying the equation:
0 = -22 m/s / time
This implies that time is 0, which is incorrect. Since the car is not capable of stopping instantly, there must be some duration of time for it to come to rest. It is likely that the impact time is very short, perhaps in the order of milliseconds, and it is not provided in the given information. Without knowing the impact time, we cannot determine the average velocity during the collision accurately.
Hence, we cannot determine the average velocity during the collision without additional information.