The modern grocery has cashews that sell for $4.00 a pound and peanuts that sell for 2.50 a pound. How much of each must Albert the grocer mixed to get 60 pounds of mixture that he can sell for three dollars per pound? Express the problem as a system of linear equations and solve using the method of your choice
You've had a lot of answers this morning. Now it's your turn. How do YOU think you should solve this problem?
C+ p=60
4.00c+2.50p=3.00*60
But how after that
Taylor, we have done this many times now
from the first line, p = 60 - c
use that (60-c) for p in the second line
To solve this problem using a system of linear equations, let's assign variables:
Let x represent the pounds of cashews.
Let y represent the pounds of peanuts.
We can set up the following system of equations based on the given information:
Equation 1: x + y = 60 (since Albert wants to make a mixture of 60 pounds)
Equation 2: 4x + 2.5y = 3*(x + y) (since he wants to sell the mixture for $3 per pound)
To simplify Equation 2, let's distribute the 3 on the right side:
Equation 2: 4x + 2.5y = 3x + 3y
Now we have a system of linear equations:
Equation 1: x + y = 60
Equation 2: 4x + 2.5y = 3x + 3y
To solve this system, we can use any method we prefer, such as substitution or elimination. Let's solve it using elimination.
Multiply both sides of Equation 1 by 2.5 to make the coefficients of y the same:
Equation 1: 2.5x + 2.5y = 150
Now we can subtract Equation 2 from Equation 1 to eliminate the y term:
(2.5x + 2.5y) - (4x + 2.5y) = 150 - (3x + 3y)
This simplifies to:
2.5x + 2.5y - 4x - 2.5y = 150 - 3x - 3y
Combine like terms:
-1.5x = -3x + 150
Add 3x to both sides:
-1.5x + 3x = -3x + 3x + 150
This simplifies to:
1.5x = 150
Divide both sides by 1.5:
x = 100
Now substitute the value of x back into Equation 1:
100 + y = 60
Subtract 100 from both sides:
y = -40
Since we cannot have a negative weight of peanuts, we need to check our calculations.
Let's substitute x = 100 back into Equation 2 to see if it matches the given information:
4(100) + 2.5y = 3(100 + y)
400 + 2.5y = 300 + 3y
Subtract 2.5y from both sides:
400 = 300 + 0.5y
Subtract 300 from both sides:
100 = 0.5y
Multiply both sides by 2:
200 = y
Now we have the correct values:
x = 100 (pounds of cashews)
y = 200 (pounds of peanuts)
Albert should mix 100 pounds of cashews with 200 pounds of peanuts to get a 60-pound mixture that he can sell for $3 per pound.