# physics

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An automobile tire has a pressure of 325 kPa when the temperature is 10 degrees Celsius. If the temperature of the tire rises to 50 degrees Celsius and its volume is constant,what is the new pressure?

• physics -

P V = n R T
here
V, n and R are constant so
P1/T1 = P2/T2
Pi = 325 k Pa
T1 = 10 + 273 = 283
T1 = 50 + 273 - 323

P2 = P1 T2/T1

• physics -

4x10^2 KPa

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