A proton has a charge of e= 1.6 x 10^-19 C. (a.) Calculate the electric field produced by the proton 10 cm away. (b.) what is the magnitude of the electric potential at the same position (10cm)?
To calculate the electric field produced by a proton at a given distance, you can use the formula for electric field strength:
Electric field (E) = (k * Q) / r^2
Where:
- E is the electric field strength
- k is the electrostatic constant (approximately 9.0 x 10^9 N m^2/C^2)
- Q is the charge of the proton (1.6 x 10^-19 C)
- r is the distance from the proton (0.10 m)
(a.) Calculation for electric field:
Electric field (E) = (9.0 x 10^9 N m^2/C^2 * 1.6 x 10^-19 C) / (0.10 m)^2
E = 144 N/C
So, the electric field produced by the proton at a distance of 10 cm is 144 N/C.
(b.) To calculate the magnitude of the electric potential at the same position, you can use the formula for electric potential:
Electric potential (V) = (k * Q) / r
Where:
- V is the electric potential
- k is the electrostatic constant (approximately 9.0 x 10^9 N m^2/C^2)
- Q is the charge of the proton (1.6 x 10^-19 C)
- r is the distance from the proton (0.10 m)
(b.) Calculation for electric potential:
Electric potential (V) = (9.0 x 10^9 N m^2/C^2 * 1.6 x 10^-19 C) / (0.10 m)
V = 1440 V
So, the magnitude of the electric potential at a distance of 10 cm is 1440 V.