A basketball player makes 80% of her free throws. Recently during a very close game, she shot 5 free throws near the end of the game and missed 3 of them. The fans booed. What is the probability of her missing 3 (or more) free throws out of 5? Set up and conduct a simulation (using the random digits below) with 10 repetitions.
8323460278436012763012608726876805665109324646108127541745017491243217468017649817480716408712807408783402746237416207
48648148631085738
DO I USED THE NUMBERS 0 - 7 OR 1 - 8
0 1 2 3 4 5 6 7 OR 1 2 3 4 5 6 7 8
BELOW I USED 1-7 AND DID NOT USED ZERO HAS A FREE THROW
83234=MHHHH ALL HIT
60278=HMHHM MISS TWO
43601=HHHMH MISS ONE
27630=HHHHM MISS ONE
12608=HHHMM MISS TWO
72687=HHHMH HIT ALL
68056=HMMHH MISS ONE
6 5109=HHHMM MISS TWO
32464=HHHHH HIT ALL
61081=HHMMH MISS ONE
5 of 5 3
4 of 5 4
3 of 5 3
2 of 5 0
1 of 5
0 fo 5
Your title gives no hint as to if you need an English or Latin teacher or whatever, wasting everyone's time.
To calculate the probability of the basketball player missing 3 (or more) free throws out of 5, we need to perform a simulation using the given random digits.
First, let's assign numbers 1-7 to represent a successful free throw and numbers 8-9 to represent a missed free throw. Since we want to calculate the probability of missing 3 or more out of 5 free throws, we can ignore the zeros in the random digits.
Now, let's go through the given random digits and conduct the simulation 10 times:
1. Simulation 1: Using the digits 8, 3, 2, 3, 4, representing missed, successful, successful, successful, successful, respectively, the player misses 1 free throw out of the 5.
2. Simulation 2: Using the digits 6, 0, 2, 7, 8, representing missed, successful, successful, missed, missed, respectively, the player misses 2 free throws out of the 5.
3. Simulation 3: Using the digits 4, 3, 6, 0, 1, representing successful, successful, successful, missed, successful, respectively, the player misses 1 free throw out of the 5.
4. Simulation 4: Using the digits 2, 7, 6, 3, 0, representing successful, successful, successful, successful, missed, respectively, the player misses 1 free throw out of the 5.
5. Simulation 5: Using the digits 1, 2, 6, 0, 8, representing successful, successful, successful, missed, missed, respectively, the player misses 2 free throws out of the 5.
6. Simulation 6: Using the digits 7, 2, 6, 8, 7, representing successful, successful, successful, missed, successful, respectively, the player misses 1 free throw out of the 5.
7. Simulation 7: Using the digits 6, 8, 0, 5, 6, representing missed, successful, successful, successful, missed, respectively, the player misses 1 free throw out of the 5.
8. Simulation 8: Using the digits 6, 5, 1, 0, 9, representing successful, successful, successful, missed, missed, respectively, the player misses 2 free throws out of the 5.
9. Simulation 9: Using the digits 3, 2, 4, 6, 4, representing successful, successful, successful, successful, successful, respectively, the player hits all 5 free throws.
10. Simulation 10: Using the digits 6, 1, 0, 8, 1, representing successful, successful, missed, missed, successful, respectively, the player misses 2 free throws out of the 5.
Calculating the total number of simulations with 3 or more missed free throws, we have:
1 simulation with 1 missed free throw
4 simulations with 2 missed free throws
0 simulations with 3 missed free throws
0 simulations with 4 missed free throws
0 simulations with 5 missed free throws
Therefore, out of the 10 simulations, 5 had 2 or fewer missed free throws.
To calculate the probability, we can divide the number of simulations with 3 or more missed free throws by the total number of simulations. In this case, the probability would be 0.
Please note that this specific simulation did not yield any scenarios with 3 or more missed free throws out of 5, so the probability is 0. However, if you repeat the simulation with a larger sample size, you will likely find some scenarios with 3 or more missed free throws, and the probability will be greater than 0.