How to find x-intercepts from x(x-2)(x+2)?
x=0, 2, -2
yes, that is where f(x) hits the x axis
Note - I made a mistake in earlier problem, note correction, scroll down
To find the x-intercepts of a polynomial, you need to determine the values of x that make the polynomial equal to zero. In this case, the polynomial given is x(x-2)(x+2).
To find the x-intercepts, you set the polynomial equal to zero:
x(x-2)(x+2) = 0
Now, you have a product of three factors equated to zero. According to the zero-product property, for a product to be equal to zero, at least one of the factors must be equal to zero.
So, you can set each factor equal to zero and solve for x:
x = 0 (since the first factor x = 0)
x - 2 = 0 (since the second factor x - 2 = 0)
x + 2 = 0 (since the third factor x + 2 = 0)
Solving these equations will give you the x-intercepts:
From the first equation, x = 0
From the second equation, x = 2
From the third equation, x = -2
Therefore, the x-intercepts of the given polynomial equation x(x-2)(x+2) are 0, 2, and -2.