solve net ionic equATION Ba(OH)2 + Na2SO4
Ba^2+(aq) + SO4^2-(aq) ==> BaSO4(s)
To solve the net ionic equation for the reaction between Ba(OH)2 (barium hydroxide) and Na2SO4 (sodium sulfate), we first need to write the balanced chemical equation.
1. Write the balanced chemical equation:
Ba(OH)2 + Na2SO4 → BaSO4 + 2 NaOH
2. Identify the soluble and insoluble compounds:
- Ba(OH)2 and Na2SO4 are both soluble compounds.
- BaSO4 is insoluble and forms a precipitate.
- NaOH is soluble.
3. Write the complete ionic equation:
Ba2+ + 2 OH- + 2 Na+ + SO4^2- → BaSO4 (s) + 2 Na+ + 2 OH-
4. Write the net ionic equation:
Ba2+ + SO4^2- → BaSO4 (s)
In the net ionic equation, we remove the spectator ions (ions that appear on both sides of the equation in the same form) since they do not participate in the chemical reaction. Therefore, only the barium ion (Ba2+) and sulfate ion (SO4^2-) contribute to the formation of the insoluble barium sulfate (BaSO4) precipitate.
To solve the net ionic equation for the reaction between barium hydroxide (Ba(OH)2) and sodium sulfate (Na2SO4), we first need to write the balanced molecular equation:
Ba(OH)2 + Na2SO4 --> BaSO4 + 2NaOH
Next, we can break down the soluble compounds into their respective ions:
Ba(OH)2 breaks down into Ba2+ and 2OH-
Na2SO4 breaks down into 2Na+ and SO4(2-)
Since barium sulfate (BaSO4) is insoluble, it will not dissociate into ions. However, sodium hydroxide (NaOH) is soluble, and we can break it down:
NaOH dissociates into Na+ and OH-
Now, we can write the complete ionic equation, including all the dissociated ions:
Ba2+ + 2OH- + 2Na+ + SO4(2-) --> BaSO4 + 2Na+ + 2OH-
To determine the net ionic equation, we need to eliminate the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Na+ and OH-. By removing them, we get the net ionic equation:
Ba2+ + SO4(2-) --> BaSO4
The net ionic equation shows only the ions directly involved in the reaction and simplifies the overall equation.