Mrs. Ana is holding a logic contest. The 13 students who are participating randomly draw cards that are numbered with consecutive integers from 1 to 13.
>The student who draws number 1 will be the host.
>The students who draw the other odd numbers will be on the red team.
>The students who draw the even numbers will be on the blue team.
One student has already drawn a card and is on the blue team. If Kiko is the next student to pick a card, what is the probability that he will be on the red team?
so, we know that now there are 12 cards left: 5 even and 6 odd and #1
P(red) = 6/12
r u gr 7?
To find the probability that Kiko will be on the red team, we need to determine the number of favorable outcomes divided by the total number of possible outcomes.
There are 13 students in total, and one student (who is already on the blue team) has already drawn a card. So, there are 12 cards remaining to be drawn by Kiko and the other students.
Out of the 12 remaining cards, there are 6 odd-numbered cards (representing the red team) and 6 even-numbered cards (representing the blue team). Kiko will be on the red team if he draws an odd-numbered card.
Therefore, the number of favorable outcomes is 6 (since there are 6 odd-numbered cards) and the total number of possible outcomes is 12 (since there are 12 remaining cards).
Hence, the probability that Kiko will be on the red team is 6/12, which simplifies to 1/2 or 0.5.