A 71.0 kg diver steps off a diving board and drops straight down into the water. The water provides an upward average net force 1110 N. If the diver comes to rest 4.1 m below the water's surface, what is the total distance between the diving board and the diver's stopping point underwater?
resisting net force*distance=PE at top of board.
1110*4.1=71*g*h solve for h. height h is the total distance from the board to the stopping point.
This is simply incorrect.
I agree, bob is using the PE equation (deltaPE=mgh)
To find the total distance between the diving board and the diver's stopping point underwater, we need to consider the forces acting on the diver.
The force of gravity acting on the diver can be calculated using the formula:
Weight = mass × acceleration due to gravity
Given that the mass of the diver is 71.0 kg and the acceleration due to gravity is approximately 9.8 m/s², we can find the weight of the diver:
Weight = 71.0 kg × 9.8 m/s²
The net force acting on the diver is the difference between the upward force provided by the water and the downward force of gravity:
Net force = Upward force - Weight
Given that the net force is 1110 N, we can calculate the upward force provided by the water:
Upward force = Net force + Weight
Now, since the diver comes to rest 4.1 m below the water's surface, we can assume that the upward force of the water equals the force due to gravity at this point. Therefore, we can use the formula:
Force = mass × acceleration
But in this case, the acceleration is not the acceleration due to gravity, since the diver is not moving up or down anymore and has come to a stop. So we need to find the acceleration that would cause the diver to stop at 4.1 m below the surface.
To do this, we'll use the equation of motion:
vf^2 = vi^2 + 2ad
Where:
vf is the final velocity (which is 0 since the diver has come to a stop),
vi is the initial velocity (which is 0 since the diver starts from rest),
a is the acceleration, and
d is the displacement (which is 4.1 m in this case).
Since vi and vf are 0, the equation simplifies to:
0 = 0 + 2ad
Rearranging for acceleration:
a = 0 / (2d)
Since a divided by zero is undefined, we can conclude that the acceleration is 0.
Therefore, the upward force provided by the water is equal to the weight of the diver (force due to gravity):
Upward force = Weight
Now, we can calculate the weight of the diver as mentioned above:
Weight = 71.0 kg × 9.8 m/s²
Finally, the total distance between the diving board and the diver's stopping point underwater is the sum of the distance traveled by the diver due to the upward force provided by the water and the initial distance between the diving board and the water's surface.
Total distance = distance due to upward force + distance between diving board and water's surface
Distance due to upward force can be calculated using the equation of motion again:
vf^2 = vi^2 + 2ad
In this case, vi is 0, vf is the initial velocity of the diver, a is the acceleration (which is 0 since the diver has come to a stop), and d is the displacement (which is 4.1 m).
Therefore, the total distance would be:
Total distance = 4.1 m + final velocity × time
We need to find the final velocity and time to calculate the total distance. However, without additional information, we cannot determine the exact values for them.
So, the total distance between the diving board and the diver's stopping point underwater is 4.1 meters plus the distance traveled due to the upward force provided by the water.