Three minutes after take-off, and airplane is 5,000 feet in the air. If it ascends at a constant rate, what is the rate of change? Please help.
5,000 ft/3 min = 1667 feet/minute
To find the rate of change, we need to determine how much the airplane's altitude changes per unit of time. In this case, we know that the airplane ascends at a constant rate. Let's break down the information we have:
Time: 3 minutes
Altitude: 5,000 feet
To calculate the rate of change, we need to divide the change in altitude by the change in time. In this case, the change in altitude is 5,000 feet because the airplane starts at ground level.
Change in altitude: 5,000 feet
Change in time: 3 minutes
Rate of change (ascend rate) = Change in altitude / Change in time
Rate of change = 5,000 feet / 3 minutes
To simplify the units, we can convert the time from minutes to seconds since the altitude is given in feet:
1 minute = 60 seconds
Change in time = 3 minutes x 60 seconds/minute = 180 seconds
Rate of change = 5,000 feet / 180 seconds
Now, let's calculate the rate of change:
Rate of change = 27.78 feet per second
Therefore, the airplane is ascending at a rate of 27.78 feet per second.