Precalculus
posted by Steve .
Given: f(x) = X^2x
evaluate: f(sqrt2 + 3)
I have worked out this and am stuck:
(sqrt2+3)^2  (sqrt2+3)
(sqrt2+3)*(sqrt2+3) (sqrt2 +3)
(sqrt2)^2+ 3sqrt2 +3sqrt2+ 9 (sqrt2+3)
2+6sqrt2 +9sqrt23
and am stuck or wrong here. Ans= SQRT2+6sqrt2 all under radical
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