Chem

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S2 + C ----> CS2

How many grams of CS2 can be prepared by heating 11.0 moles of S2 with excess carbon in 5.20 L reaction vessel held at 900 kelvin until equilibrium is attained?

Kc= 9.40

  • Chem -

    (S2) = 11.0mols/5.20L = approx 2 but you need to be more accurate.
    .........S2 + C ==> CS2
    I mols...2..xs...0
    C.......-x..xs...x
    E......2-x..xs...x

    Kc = (CS2)/(S2) note:C doesn't appear in the Kc exprssion because it is a solid.

    Substitute the E line into Kc expression and solve for x = (CS2) = M in mols/L.
    total mols = M x L = ?
    grams = mols x molar mass = ?

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