algebra2
posted by sherianna .
a chord in a circle makes an angle of 45° with the radius. if the chord is 4 cm long, what is the radius of the circle

since the chord forms the base of an isosceles triangle, the other angles are 45° and 90°. The radii form the 90° angle, so 2r^2 = 4^2, and r=2√2.