The assets(in billions of dollars) of the four wealthiest people in a particular country are 43,25,21,15 assume that samples of size n=2 are randomly selected
What is your question?
To answer this question, we need to calculate the number of possible combinations of samples of size 2 that can be selected from the four given assets.
The formula for calculating the number of combinations is given by:
nCk = n! / (k!(n-k)!)
In this case, we have n = 4 (since there are four assets) and k = 2 (since we are selecting samples of size 2).
Using the formula above, we can calculate the number of combinations as follows:
4C2 = 4! / (2!(4-2)!)
= 4! / (2!2!)
= (4 * 3 * 2 * 1) / [(2 * 1) * (2 * 1)]
= (24) / [(4) * (2)]
= 24 / 8
= 3
Therefore, there are 3 possible combinations of samples of size 2 that can be selected from the four given assets.
To find the number of all possible samples of size 2, we need to use the combination formula.
The combination formula is given by:
C(n, r) = n! / (r!(n - r)!)
where n is the total number of items and r is the number of items to choose at a time.
In this case, we have 4 people, so n = 4. We want to select 2 people at a time, so r = 2.
Plugging these values into the formula:
C(4, 2) = 4! / (2!(4 - 2)!)
= 4! / (2! * 2!)
= (4 * 3 * 2!) / (2! * 2!)
= 24 / (2 * 2)
= 6
There are a total of 6 possible samples of size 2 that can be selected from the four wealthiest people in the country.