Reilly used 1 and 7/10 tubes of paint to paint a model. He used 2 and 3/8 tubes to finish an art project. How many tubes did he use in total ?
1 7/10 + 2 3/8
1 28/40 + 2 15/40 = 3 43/40 = 4 3/40
To find the total number of tubes of paint Reilly used, we need to add the number of tubes he used for painting the model and the number of tubes he used for the art project.
Given that Reilly used 1 and 7/10 tubes of paint for the model and 2 and 3/8 tubes of paint for the art project, we'll first add the whole numbers together:
1 + 2 = 3
Now, let's add the fractions:
7/10 + 3/8
To add fractions with different denominators, we first need to find a common denominator. In this case, the least common multiple (LCM) of 10 and 8 is 40.
Next, we'll convert the fractions so they have the same denominator:
(7/10) * (4/4) = 28/40
(3/8) * (5/5) = 15/40
Now that both fractions have the same denominator, we can add them:
28/40 + 15/40 = 43/40
Since we need the answer in terms of whole numbers and proper fractions, we can simplify 43/40.
Divide the numerator (43) by the denominator (40):
43 ÷ 40 = 1 with a remainder of 3
So, the simplified form of 43/40 is 1 and 3/40.
Now, we can add the whole numbers (3) and the fraction (1 and 3/40):
3 + 1 and 3/40 = 4 and 3/40
Therefore, Reilly used a total of 4 and 3/40 tubes of paint.