How many ways to choose 2 boys and 3 girls from a class of 10 boys and 15 girls?
Would you do:
10C2=45
15C3=455
(45)(455)=20,475?
correct
Thank you
Yes, that is correct. To find the number of ways to choose 2 boys and 3 girls from a class of 10 boys and 15 girls, you can use the combination formula.
The number of ways to choose 2 boys from 10 boys can be calculated as 10C2, which is equal to 45. This formula calculates the number of combinations (unordered selections) of 2 objects from a set of 10 objects without replacement.
Similarly, the number of ways to choose 3 girls from 15 girls can be calculated as 15C3, which is equal to 455.
To find the total number of ways to choose 2 boys and 3 girls, you can multiply the results of 10C2 and 15C3. So, (10C2) * (15C3) = 45 * 455 = 20475.
Therefore, there are 20,475 ways to choose 2 boys and 3 girls from a class of 10 boys and 15 girls.