How much dry solution would it take to prepare 135 0.120M NaNO3 to a sovent?
I'm not sure what you mean by a dry solution. Certainly there are many but I don't think any of them apply here.
Do you mean 135 mL of 0.120 M NaNO3 in a solvent. Do you want 1 L of solution.
You want how many mols? That's M x L = ? = 0.135 x 0.120 = ?
Then mol/L = ?mols/L solution.