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physics

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If the vertical initial speed of the ball is 4.0m/s as the cannon moves horizontally at a speed of 0.70m/s , how far from the launch point does the ball fall back into the cannon?

  • physics -

    Vi = 4
    h = Hi + Vi t - 4.9 t^2

    0 = 0 + 4 t -4.9 t^2
    t = 4/4.9 = .816 seconds before it is back down

    .816 * . 7 = .571 meters

    Your cannonball is remarkably slow, typo?

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