I think I chose the correct answer.
In a closed system, two carts have a compressed spring between them. One of the carts has a total mass, including its contents, of 2.0 kg, and the other has total mass of 1.0 kg. Which cart experiences the momentum change of greater magnitude after the spring is released to push them apart?
The 1.0 kg cart has the greatest change in momentum.
The 2.0 kg cart has the greatest change in momentum.
Each has a momentum change of the same nonzero magnitude. <------
Each has zero momentum change.
Yes,
total momentum before = 0
total momentum after = 0
so
m v + M V = 0
of course the little one has higher VEOLICIY but equal and opposite momentum
OK, thanks for the help :)
You are welcome :)
To determine which cart experiences the greatest change in momentum, we need to understand the concept of momentum.
Momentum is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) is given by the equation p = m * v, where m is the mass of the object and v is its velocity.
In this scenario, both carts are initially at rest. When the compressed spring is released, it exerts a force on both carts, causing them to move in opposite directions. Since the force and time interval are the same for both carts, we can conclude that the change in momentum for each cart will be the same magnitude but opposite in direction.
Thus, the correct answer is: Each has a momentum change of the same nonzero magnitude.