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You measure the dimensions of a rectangular block of aluminum to determine its volume. It has the following dimensions.
length = 10.27 cm; width = 4.92 cm; height = 1.53 cm
Assuming that each of these measurements is accurate to the nearest 0.01 cm, find the volume of the block and the fractional error on its volume due to measurement errors.

I keep getting .007 cm^3 what am I doing wrong?

  • science -

    L min. = 10.26 cm
    W min. = 4.91 cm
    H min. = 1.52 cm

    V nom. = 10.27 * 4.92 * 1.53=77.308 cm^3

    V min. = 10.26 * 4.91 * 1.52=76.728cm^3

    Error = 77.308 - 76.728 = 0.5796 cm^3

    NOTE: The fractional error has no units;
    they cancel.

    Fractional Error = 0.58cm^3/77.308cm^3 =
    0.0075

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