so we did a chem lab and one of the questions is to tabulate the amount of S2O3 consumed in moles and times (sec) for each run.
I'm just not sure how to calculate the amount consumed. Can someone please explain how?
I assume you have a sequence of measurements of mols/grams/amount vs time in seconds.
amount at start - amount at 1 sec = amount consumed. This answer is general I know but so is your question with no data.
oh okay, that makes sense & a little obvious haha . Thanks.
To calculate the amount of S2O3 consumed in moles for each run in your chem lab, you will need to use the balanced chemical equation for the reaction involving S2O3. Once you have the equation, you can use stoichiometry to convert the given information into moles of S2O3 consumed.
Here are the steps to follow:
1. Write down the balanced chemical equation for the reaction involving S2O3. For example, if the reaction is:
2 S2O3 + I2 --> S4O6 + 2 I-
2. Identify the molar ratio between S2O3 and the other substances involved in the reaction. In this case, the ratio between S2O3 and I2 is 2:1 based on the coefficients in the balanced equation.
3. Gather the necessary information. You should have the amount of one of the reactants or products in each run, such as the amount of I2 or S4O6, and the time it took for the reaction to occur in seconds.
4. Calculate the moles of S2O3 consumed. To do this, divide the moles of the given substance (either I2 or S4O6) by the molar ratio between S2O3 and that substance. For example, if you have the moles of I2 consumed, you would divide that value by 1 (since the molar ratio is 2:1).
5. Calculate the time in seconds. The time given for each run is already in seconds.
Remember to perform these calculations for each run separately to tabulate the amount of S2O3 consumed in moles and times (sec) for each run.
Note: Make sure to follow any additional instructions that may be provided in your lab manual or by your instructor, as the specific procedure may vary.