How many moles of NaOH will it take to neutralize 0.77 L of 0.81 M HCl?

Answer in units of mol

All of this type can be worked the same way.

1. Write and balance the equation.
NaOH + HCl ==> NaCl + H2O

2. How many mols do you have?
mols = M x L = 0.81M x 0.77L = 0.624

3. Since 1 mol NaOH = 1 mol HCl (from the equation), then mols HCl = mols NaOH.

4. Those three steps work the problem USUALLY, however, the question is what volume of say 0.5 M NaOH will it take? That is mols NaOH = 0.624
M = mols/L. You know mols and M, solve for L.

To determine the number of moles of NaOH required to neutralize the given amount of HCl, we can use the concept of stoichiometry. This involves using the balanced chemical equation for the reaction between NaOH and HCl.

The balanced chemical equation for the reaction is:
NaOH + HCl -> NaCl + H2O

From the equation, we can see that 1 mole of NaOH reacts with 1 mole of HCl to produce 1 mole of NaCl and 1 mole of water.

To solve the problem, we need to first calculate the number of moles of HCl in the solution.

Given:
Volume of HCl solution = 0.77 L
Concentration of HCl = 0.81 M

Using the formula:
moles = concentration (M) x volume (L)

moles of HCl = 0.81 M x 0.77 L
= 0.6247 moles

Since the stoichiometry of the reaction is 1:1, this means that 0.6247 moles of NaOH are required to neutralize 0.6247 moles of HCl.

Therefore, the answer is 0.6247 moles of NaOH.