What is the instantaneous velocity of a freely falling object 7.0s after it is released from a position of rest?
What is its average velocity during this 7.0-s interval?
How far will it fall during this time?
Well, the instantaneous velocity of a freely falling object 7.0s after it is released from rest is... wait for it... fall-tastic! It's actually equal to the velocity it reaches after falling for 7 seconds.
To calculate the velocity, we can use the equation v = gt, where g is the acceleration due to gravity (approximately 9.8 m/s^2) and t is the time. Plugging in the values, we get v = 9.8 m/s^2 * 7s. Just multiply those numbers and you'll find the velocity, which I like to call the "speed of falling love".
Now, when it comes to average velocity during this 7.0s interval, it's actually the total distance traveled divided by the time taken. Since it's a freely falling object, the average velocity is the same as the instantaneous velocity we just calculated! So, go ahead and use that value to impress your physics teacher.
Lastly, to find out how far it will fall during this time, we can use the equation d = 1/2 gt^2, where d represents the distance. Now, don't worry about the math! Since we know the time is 7 seconds and g is approximately 9.8 m/s^2, all you need to do is square 7, multiply by 9.8, and divide by 2. Voila! You've got the distance the object will fall.
So, there you have it – some physics fun with a touch of falling laughter!
To find the instantaneous velocity of a freely falling object 7.0s after it is released from a position of rest, we can use the formula:
v = gt
where:
v is the velocity of the object
g is the acceleration due to gravity (which is approximately 9.8 m/s^2)
t is the time elapsed (in seconds)
So, plugging in the values:
v = (9.8 m/s^2) * (7.0 s)
v ≈ 68.6 m/s
Therefore, the instantaneous velocity of the object is approximately 68.6 m/s.
To find the average velocity during this 7.0-s interval, we can use the formula:
average velocity = (final velocity - initial velocity) / time
Since the object starts from rest, the initial velocity is 0 m/s. We already found the final velocity to be 68.6 m/s and the time to be 7.0 s:
average velocity = (68.6 m/s - 0 m/s) / 7.0 s
average velocity ≈ 9.8 m/s
Therefore, the average velocity during this 7.0-s interval is approximately 9.8 m/s.
To find how far the object will fall during this time, we can use the formula:
distance = (initial velocity * time) + (1/2 * acceleration * time^2)
Since the object starts from rest, the initial velocity is 0 m/s and the acceleration is 9.8 m/s^2. Plugging in the values:
distance = (0 m/s * 7.0 s) + (1/2 * 9.8 m/s^2 * (7.0 s)^2)
distance = 0 m + (1/2 * 9.8 m/s^2 * 49 s^2)
distance = 0 m + 240.1 m
distance ≈ 240.1 m
Therefore, the object will fall approximately 240.1 meters during this 7.0-s time interval.
To find the instantaneous velocity of a freely falling object 7.0 seconds after it is released from a position of rest, you can use the equation for the velocity of an object in free fall: v = gt, where v is the velocity, g is the acceleration due to gravity, and t is the time.
First, let's determine the acceleration due to gravity, which is approximately -9.8 m/s² near Earth's surface. The negative sign indicates that the acceleration is directed downward.
Substituting the values into the equation, we have v = (-9.8 m/s²)(7.0 s) = -68.6 m/s.
Therefore, the instantaneous velocity of the object 7.0 seconds after it is released is -68.6 m/s. The negative sign indicates that the velocity is directed downward.
To find the average velocity during this 7.0-second interval, you can use the formula: average velocity = (final velocity + initial velocity) / 2.
Since the object starts from a position of rest, the initial velocity is 0 m/s. The final velocity after 7.0 seconds is -68.6 m/s. Plugging these values into the formula, we have average velocity = (0 m/s + (-68.6 m/s)) / 2 = -34.3 m/s.
Therefore, the average velocity during this 7.0-second interval is -34.3 m/s. Again, the negative sign indicates a downward direction.
To determine the distance the object will fall during this time, we can use the equation for the distance fallen during free fall: d = (1/2)gt², where d is the distance, g is the acceleration due to gravity, and t is the time.
Substituting the values, we have d = (1/2)(-9.8 m/s²)(7.0 s)² = (1/2)(-9.8 m/s²)(49.0 s²) = -240.1 m.
Therefore, the object will fall approximately 240.1 meters during this 7.0-second interval. The negative sign indicates that the distance is measured downward.
v=g*t
average velocity=distance/time= 1/2 g t^2/t
= 1/2 g t
distance=1/2 g t^2