Find two numbers whose sum is 39 and the greater number exceeds the smaller one by five.
smaller ---- x
larger ------x+5
x + x+5 = 39
continue...
2x + 5 = 39
2x = 5 - 5 = 39 - 5
2x = 34
2 = 17
1st # = 17
2nd # = 17+5 or 22
22 + 17 = 39
hrtrt
To find two numbers whose sum is 39 and the greater number exceeds the smaller one by five, we can set up a system of equations.
Let's assume the smaller number is x, and the greater number is y.
According to the given information, the sum of the two numbers is 39:
x + y = 39 (Equation 1)
It is also given that the greater number exceeds the smaller one by five:
y = x + 5 (Equation 2)
Now, we have a system of equations consisting of Equation 1 and Equation 2. To solve this system, we can use the method of substitution or elimination.
Substitution Method:
We can solve Equation 2 for y, and then substitute it into Equation 1:
From Equation 2, we know that y = x + 5. Substitute this into Equation 1:
x + (x + 5) = 39
2x + 5 = 39
2x = 39 - 5
2x = 34
x = 34/2
x = 17
Now substitute the value of x back into Equation 2 to find y:
y = x + 5
y = 17 + 5
y = 22
So, the smaller number is 17, and the greater number is 22.
Therefore, the two numbers whose sum is 39 and the greater number exceeds the smaller one by five are 17 and 22.