the first aircraft has 47 more seats than the second aircraft. the third aircraft has 54 fewer seats than the second aircraft. if their total number of seats is 401, find the number of seats for each aircraft.

Let x = second, then x+47 = first and x-54 = third.

x + (x+47) + (x-54) = 401

Solve for x, then the others.

To solve this problem, let's assign variables to the unknowns. Let's call the number of seats in the second aircraft "x".

According to the problem, the first aircraft has 47 more seats than the second aircraft, so its number of seats is "x + 47".

Similarly, the third aircraft has 54 fewer seats than the second aircraft, so its number of seats is "x - 54".

The total number of seats for all three aircraft is given as 401, so we can write the equation:

(x) + (x + 47) + (x - 54) = 401

Simplifying the equation, we have:

3x - 7 = 401

Adding 7 to both sides of the equation:

3x = 408

Finally, dividing both sides of the equation by 3:

x = 136

Therefore, the second aircraft has 136 seats.

Substituting this value back into the earlier expressions, we can find the number of seats for the first and third aircraft:

The first aircraft has: x + 47 = 136 + 47 = 183 seats.
The third aircraft has: x - 54 = 136 - 54 = 82 seats.

So, the number of seats for each aircraft is as follows:
First aircraft: 183 seats
Second aircraft: 136 seats
Third aircraft: 82 seats.