A couple wishes to rent a car for one day while on vacation. Ford Auto Rental wants $35.00 per day and 14¢ per mile, while Chevrolet-For-A-Day wants $34.00 per day and 16¢ per mile. After how many miles would the price to rent the Chevrolet exceed the price to rent a Ford?
f=35+15m
c=34+16m
if c>f
34+16m>35+15m
subtract 34 from each side, then subtract 15m from each side.
m>1 so at 1.05 miles, the c exceeds the f.
Ford rental: cost = 35 + .14x, where x is the number of miles
Chevy rental: cost = 34 + .16x
when is 34 + .16x > 35 + .14x
.02x > 1
x > 1/.02
x > 50
Thanks Reiny
To find out after how many miles the price to rent the Chevrolet would exceed the price to rent a Ford, we need to determine the point at which the total cost of renting the Chevrolet becomes higher than the total cost of renting the Ford.
Let's assume that x represents the number of miles driven.
For the Ford Auto Rental, the total cost can be calculated using the formula:
Total Cost for Ford = $35.00 (daily rental fee) + (0.14 cents per mile) * x
For the Chevrolet-For-A-Day, the total cost can be calculated using the formula:
Total Cost for Chevrolet = $34.00 (daily rental fee) + (0.16 cents per mile) * x
We want to find the point at which the Total Cost for Chevrolet exceeds the Total Cost for Ford, so we set up the equation:
$34.00 + (0.16 cents per mile) * x > $35.00 + (0.14 cents per mile) * x
Now, let's solve the equation to find the value of x:
$34.00 + 0.16x > $35.00 + 0.14x
0.16x - 0.14x > $35.00 - $34.00
0.02x > $1.00
x > $1.00 / 0.02
x > 50
Therefore, after 50 miles, the price to rent the Chevrolet would exceed the price to rent a Ford.