The perimeter of a pool is 64 feet and has a width of x and a length of x-4. What is both the width and length of the pool?

It is wider than it is long ?

what's in a name?

2(x + x-4) = 64
2(2x-4) = 64
2x-4 = 32
2x = 36
x = 18

The pool is 18x14

To find the width and length of the pool, we'll use the information given about its perimeter.

The perimeter of a rectangle is equal to the sum of all four sides. In this case, the given perimeter is 64 feet.

The formula for the perimeter of a rectangle is:
Perimeter = 2 * (length + width)

Let's substitute the given values into the formula:
64 = 2 * (x + (x-4))

Simplify the equation:
64 = 2 * (2x - 4)

Expand the right side of the equation:
64 = 4x - 8

Now, let's isolate the variable 'x' by moving terms around:
4x = 64 + 8
4x = 72

Divide both sides of the equation by 4 to solve for 'x':
x = 72 / 4
x = 18

Therefore, the width of the pool is 'x' and the length is 'x-4'. Substituting the value of 'x', we find that the width is 18 feet and the length is 14 feet.