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(16e^12)^1/3
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16^(1/3) e^4
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A 0.0170 M solution of an acid has a pH of 2.5. What is the pKa?
i did 10^-2.5=3.16e-3 Then 0.0170 - 3.16e-3=0.01384 ka=
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Very good work.
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(16e^12)^1/3
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done before, look back
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What is 2.16e+16 billion
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What a weird question. 1 billion is 10^9 2.16E+16 billion is thus 2.16*10^16 * 10^9 = 2.16 * 10^25
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sqrt to the power of 3 (16e^12)
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To calculate the expression sqrt(16e^12) raised to the power of 3, you need to follow these steps:
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5/8(16e + 24f - 56g) =
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5/8 * 16e = 10e and so on
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If (2x-1)^4 = ax^4+bx^3+cx^2+dx+e then find the value of a+2b +4c+8d+16e..plz help easy way..
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To find the value of a+2b+4c+8d+16e, we need to expand the expression (2x-1)^4 and then use the
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Solve the following equation for x in terms of ln and e.
(2e^3)-6-(16e^-x)=0
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just chug away as usual 2e^3 - 6 - 16e^-x = 0 16e^-x = 2e^3 - 6 e^-x = (e^3-3)/8 e^x = 8/(e^3-3) x =
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please help factor prime expression 4k^2+20k+25
16e^2-4 thank you thank you
For what values of x is the graph of
y = 8e^−x^2 concave down? (Enter your answer using interval notation.) I started by
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the graph is concave down where 16e^-x^2 (2x^2-1) < 0 that is where 2x^2-1 < 0 x^2 < 1/2 so, f is
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What would the [OH-] be after addition of 17.47 mL of 0.1000 M NaOH to 25.00 mL of 0.1000 HA (a weak acid, Ka = 3.16e-4)?
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millimols NaOH = mL x m = 17.47 x 0.1 = 1.747 millimols HA = 25 x 0.1 = 2.5 .........HA + NaOH ==>
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