Algebra

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Ten years ago a man was three times as old as his son. In twelve more years,the son is three fifths as old as his father.what were their ages 5 years ago?

  • Algebra -

    10 years ago:

    son --- x
    father --- 3x

    NOW:
    son --- x+10
    father --- 3x+10

    12 years from now:
    son --- x+22
    father -- 3x + 22

    x+22 = (3/5)(3x + 22)
    times 5
    5x + 110 = 9x + 66
    -4x = -44
    x = 11

    so 5 years ago:
    son = present age - 5
    = (11+10) - 5 = 16
    father = 3x+10 - 5 = 38

    So 5 years ago, the son was 16, and the father was 38

    (right now the son is 21, and the father is 43)

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