# physics

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An electron passes location
h0.02m, 0.04m,−0.06mi, and 4 μs later is de-
tected at location h0.02 m, 1.84 m,−0.86 mi.
Find the average velocity of the elecron:
¯v = <vx, vy, vz>

If the electron continues to travel at this av-
erage velocity, find where it will be in another
9 μs :
~d = <dx, dy, dz>

• physics -

dx=(xf-xi)

vx=dx/dt=dx/4E-6

similarlly, vy, vz.

then for the second part, knowing the velocities

xf=xi+vx*dt

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